(Q11) A bag contains a red ball, a blue ball and an yellow ball, all the balls being of the same size. Manasa takes out a ball from the bag without looking into it. What is the probability that she takes a (i) yellow ball? (ii) red ball? (iii) blue ball?

Solution :

Manasa takes out a ball from the bag without looking into it. So, it is equally likely that she takes out any one of them

Let Y be the event 'the ball taken out is yellow', B be the event 'the ball taken out is blue', and R be the event 'the ball taken out is red'

Now, the number of possible outcomes = .

  (i) The number of outcomes favourable to the event Y = .

.

  So, P(Y) =
Similarly, P(R) =
and P(B) =